Simple Method To Find Hybridization

How Many Of You Have Problem With The Concept Of Hybridisation?

Very Sorry That You Will Have To Say Good Bye To Your Problem After Reading This.
Number of hybridised orbitals= 
S+1/2(E-V-C)

S: surrounding atoms
E: Electrons in the outer shell
V: total valency of surrounding atoms
C: charge

this is the one and only one equation thats going to help you.
*EXAMPLE 1
CH4
central atom: C

number of atoms surrounding central atom(S)=4
number of valence electrons of carbon( E) = 4
valancy of surrounding atoms(V)= 4*1=4
Charge (C)= 0

so number of hybridised orbitals= 4+1/2(4-4-0)
=4+1/2(0)
=4

number of hybridised orbitals is 4. So hybridisation is sp3.

Note : in determining 'V'( total valency of surrounding atoms) almost all elements like Cl, Br, I, F, H have valency 1 and everyone know O and S are bivalent.
That is valency 2.
*Example 2

ClO4 minus (charge minus one)
central: Cl
S= 4
E= 7
V= 4*2=8
C= -1

number of hybrid orbital= 4+1/2( 7-8+1)
=4

here also its sp3 hybridisation.
*EXAMPLE : 3

XeF2
Central: Xe
S=2
E=8
V= 2*1=2
C=0

2+1/2(8-2-0)=5

so hybridisation is sp3d.